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435.75=x^2+50x
We move all terms to the left:
435.75-(x^2+50x)=0
We get rid of parentheses
-x^2-50x+435.75=0
We add all the numbers together, and all the variables
-1x^2-50x+435.75=0
a = -1; b = -50; c = +435.75;
Δ = b2-4ac
Δ = -502-4·(-1)·435.75
Δ = 4243
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-\sqrt{4243}}{2*-1}=\frac{50-\sqrt{4243}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+\sqrt{4243}}{2*-1}=\frac{50+\sqrt{4243}}{-2} $
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